In a particular thermodynamic process, a gas releases 250 J of heat to its surroundings while 600 J of work is done on it. What is the change in internal energy of the gas?

Step-by-step solution

According to the first law of thermodynamics: Q = U + W Since heat is released by the gas to the surroundings, Q = -250 J. Since work is done on the gas, W = -600 J. Substituting these values into the first law equation: -250 = U - 600 U = 600 - 250 = +350 J Answer: +350 J