When 50 mL of pure oxygen gas is subjected to silent electric discharge, a portion of it is converted into ozone. If the total volume of the resulting gaseous mixture is 46 mL under similar conditions of temperature and pressure, the composition of the gaseous mixture is :

Step-by-step solution

The balanced chemical equation for the conversion of oxygen to ozone is: 3 O ₂(g) 2 O ₃(g) Let the volume of O ₂ converted into O ₃ be x mL. Volume of O ₃ formed = 2 3 x mL Volume of O ₂ remaining = (50 - x) mL The total volume of the gaseous mixture is given as 46 mL. (50 - x) + 2 3 x = 46 50 - x 3 = 46 x 3 = 4 x = 12 mL Volume of O ₂ remaining = 50 - 12 = 38 mL Volume of O ₃ formed = 2 3 12 = 8 mL The composition of the gaseous mixture is 38 mL of O ₂ and 8 mL of O ₃ . Answer: 38 mL of O ₂ , 8 mL of O ₃