An ideal gas undergoes an expansion process such that its pressure is directly proportional to its volume ( P V ). Consider the following statements: A. The temperature of the gas remains constant. B. The work done by the gas is positive. C. The internal energy of the gas increases. D. Heat is rejected by the gas. E. Heat is absorbed by the gas. Choose the correct answer from the options given below:

Step-by-step solution

Given that the process follows P V , we can write P = kV , where k is a positive constant. From the ideal gas equation, PV = nRT . Substituting P = kV , we get (kV)V = nRT T = k nR V^2 . Since the gas expands, its volume V increases. Therefore, the temperature T of the gas increases. This means the change in internal energy U is positive ( U > 0 ). Thus, statement C is correct and statement A is incorrect. During expansion, the volume increases, so the work done by the gas is positive ( W > 0 ). Thus, statement B i