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JEE MainChemistryAldehydes and Ketones

Ethyl 4-oxopentanoate is subjected to the following sequence of reactions: (i) Ethylene glycol, dry HCl (ii) Excess CH₃MgBr (iii) H₃O^+ The major product formed is:

Options

  1. AEthyl 4-hydroxy-4-methylpentanoate
  2. B2,5-Dimethylhexane-2,5-diol
  3. CHexane-2,5-dione
  4. D5-Hydroxy-5-methylhexan-2-one

Correct answer

D. 5-Hydroxy-5-methylhexan-2-one

Step-by-step solution

The starting material is ethyl 4-oxopentanoate ( CH₃-CO-CH₂-CH₂-COOCH₂CH₃ ). Step (i): Reaction with ethylene glycol and dry HCl selectively protects the ketone group by forming a cyclic acetal (1,3-dioxolane derivative). The ester group remains unreactive under these conditions. Step (ii): The protected compound is treated with excess CH₃MgBr . The Grignard reagent reacts with the ester group. Two equivalents of CH₃MgBr are consumed by the ester to form a tertiary alkoxide ( -C(O^-MgBr^+)(CH₃)₂ ). Step (iii): Acid

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