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JEE MainPhysicsCapacitance

A bridge circuit ABCD is connected to a 20 V ideal battery. The positive terminal of the battery is connected to node A and the negative terminal to node C. The arms of the bridge have the following components: arm AB contains a 3 , resistor, arm BC contains a 2 , resistor, and arm AD contains a 5 , resistor. Arm DC contains an ideal diode with its cathode connected to node D and its anode connected to node C. A 4 ,

Options

  1. A288 , J
  2. B128 , J
  3. C48 , J
  4. D576 , J

Correct answer

A. 288 , J

Step-by-step solution

Let the potential at node C be 0 V . Then the potential at node A is 20 V . In the steady state, the capacitor acts as an open circuit, so no steady current flows between B and D. For the branch ADC, the diode has its anode at C ( 0 V ) and its cathode at D. Since node D is connected to the positive terminal A via the 5 , resistor, the potential at D will be higher than at C, making the diode reverse-biased. It will act as an open circuit. Because the diode is open, no current flows through arm AD. Therefore, there

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