The limiting molar conductivity of an aqueous solution of an electrolyte of type M₂X (where M^+ is a monovalent cation and X²⁻ is a divalent anion) is 260 ~S~cm ^2 ~mol ⁻¹ . If the limiting molar ionic conductivity of the cation M^+ is 50 ~S~cm ^2 ~mol ⁻¹ , the limiting molar ionic conductivity of the anion X²⁻ is :

Step-by-step solution

According to Kohlrausch's law of independent migration of ions, the limiting molar conductivity of the electrolyte M₂X is given by: ^ _ m (M₂X) = 2 ^ _ m (M^+) + 1 ^ _ m (X²⁻) Substituting the given values: 260 = 2(50) + ^ _ m (X²⁻) 260 = 100 + ^ _ m (X²⁻) ^ _ m (X²⁻) = 260 - 100 = 160 ~S~cm ^2 ~mol ⁻¹ Answer: 160 ~S~cm ^2 ~mol ⁻¹