A circuit is constructed with four capacitors C₁ , C₂ , C₃ , and C₄ between terminals A and B . The connections are as follows: C₁ is connected between terminal A and an internal node X . C₂ is connected between node X and terminal A . C₃ is connected between terminal A and terminal B . C₄ is connected between node X and terminal B . Initially, all four capacitors have a capacitance of 2 , F . A dielectric slab of un

Step-by-step solution

Based on the given connections, we can identify the circuit topology: - C₁ and C₂ are both connected between terminal A and node X . Therefore, they are in parallel. - C₄ is connected between node X and terminal B , so it is in series with the parallel combination of C₁ and C₂ . - C₃ is connected directly between terminal A and terminal B , so it is in parallel with the entire branch containing C₁ , C₂ , and C₄ . When a dielectric of constant K is inserted into C₂ , its new capacitance becomes C₂' = 2K , F . The eq