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Given the standard reduction potentials for the following half-cells: Co²⁺(aq) + 2e⁻ Co(s) E^ = -0.28 V Au³⁺(aq) + 3e⁻ Au(s) E^ = +1.40 V Which of the following correctly represents the IUPAC notation for the spontaneous electrochemical cell formed by these half-cells and its standard cell potential?

Options

  1. ACo(s) | Co²⁺(aq) || Au³⁺(aq) | Au(s) ; E^ _ cell = +1.68 V
  2. BAu(s) | Au³⁺(aq) || Co²⁺(aq) | Co(s) ; E^ _ cell = -1.68 V
  3. CCo(s) | Co²⁺(aq) || Au³⁺(aq) | Au(s) ; E^ _ cell = +3.64 V
  4. DAu(s) | Au³⁺(aq) || Co²⁺(aq) | Co(s) ; E^ _ cell = +1.68 V

Correct answer

A. Co(s) | Co²⁺(aq) || Au³⁺(aq) | Au(s) ; E^ _ cell = +1.68 V

Step-by-step solution

For a spontaneous electrochemical cell, the standard cell potential E^ _ cell must be positive. The half-cell with the higher standard reduction potential acts as the cathode (reduction), and the one with the lower standard reduction potential acts as the anode (oxidation). Given: E^ _ Au³⁺/Au = +1.40 V E^ _ Co²⁺/Co = -0.28 V Since +1.40 V > -0.28 V, the Au³⁺/Au half-cell undergoes reduction at the cathode, and the Co²⁺/Co half-cell undergoes oxidation at the anode. According to IUPAC convention, the cell is repres

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