JEE MainPhysicsRotational Motion
A particle of mass m moves in the xy -plane with its position vector at time t given by r (t) = a ( t) i + b ( t) j , where a and b are positive constants such that a > b . Which of the following statements is correct regarding the dynamics of the particle?
Options
- AThe force acting on the particle is not directed towards the origin.
- BThe torque acting on the particle about the origin is non-zero, hence its angular momentum varies with time.
- CThe angular momentum of the particle about the origin is conserved, but its kinetic energy varies with time.
- DBoth the angular momentum about the origin and the kinetic energy of the particle remain constant.
Correct answer
C. The angular momentum of the particle about the origin is conserved, but its kinetic energy varies with time.
Step-by-step solution
Given the position vector r (t) = a ( t) i + b ( t) j . Velocity of the particle: v (t) = d r dt = -a ( t) i + b ( t) j Acceleration of the particle: a (t) = d v dt = -a ^2 ( t) i - b ^2 ( t) j = - ^2 r (t) The force acting on the particle is F = m a = -m ^2 r . Since the force is always directed opposite to the position vector, it is a central force directed towards the origin. The torque about the origin is = r F = r (-m ^2 r ) = 0 . Since the net torque is zero, the angular momentum of the particle about the ori