Cell equation : A+2 B^ + A^ 2+ +2 B A^ 2+ +2 e^ - A ; E^ =+0.34 ~V and _ 10 K=15.6 at 300 ~K for cell reactions. Find E^ for B^ + +e^ - B . [. Given : (2.303 R T)/(n F)=0.059 at .300 ~K]

Correct answer: A. 0.80 ~V aligned & E_ cell ^ =(0.059)/(2) K & E_ B^ + / B ^ -E_ A^ 2+ / A ^ =(0.059)/(2) K aligned aligned & E_ B^ + / B ^ -0.34 V=(0.059)/(2) × 15.6 & E_ B^ + / B ^ =0.46+0.34=0.80 V aligned

AIIMS 201826 May

Exam: AIIMS
Year: 2018
Date: 26 May
Subject: Chemistry
Chapter: Electrochemistry

AIIMS 2018 · 26 May · Chemistry · Electrochemistry

Cell equation : A+2 B^ + A^ 2+ +2 B A^ 2+ +2 e^ - A ; E^ =+0.34 ~V...

Cell equation :

A+2 B^{+} \longrightarrow A^{2+}+2 B A^{2+}+2 e^{-} \longrightarrow A ; E^{\circ}=+0.34 \mathrm{~V}

and

\log _{10} K=15.6

300 \mathrm{~K}

for cell reactions. Find

E^{\circ}

for

B^{+}+e^{-} \longrightarrow B

\left[\right.

Given

: \frac{2.303 R T}{n F}=0.059

\left.300 \mathrm{~K}\right]

Options

A $0.80 \mathrm{~V}$
B $1.26 \mathrm{~V}$
C $-0.54 \mathrm{~V}$
D $+0.94 \mathrm{~V}$

Correct answer

A. $0.80 \mathrm{~V}$

Step-by-step solution

\begin{aligned} & \text{ } E_{\text{cell }^{\circ}=\frac{0.059}{2} \log K \\ & E_{B^{+} / B}^{\circ}-E_{A^{2+} / A}^{\circ}=\frac{0.059}{2} \log K\end{aligned}

\begin{aligned} & E_{B^{+} / B}^{\circ}-0.34 \mathrm{ V}=\frac{0.059}{2} \times 15.6 \\ & E_{B^{+} / B}^{\circ}=0.46+0.34=0.80 \mathrm{ V}\end{aligned}

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