A sickle-cell carrier man marries a woman who is carrier for sickle-cell anaemia. What are the chances of having carrier children?

Step-by-step solution

Sickle-cell anaemia is an autosomal recessive disorder. Let the normal allele be Hb^A and the sickle-cell allele be Hb^S . The genotype of the carrier man is Hb^A Hb^S and the carrier woman is Hb^A Hb^S . The cross between them is Hb^A Hb^S Hb^A Hb^S . The possible genotypes of the offspring are: 25 %Hb^A Hb^A (Normal) 50 %Hb^A Hb^S (Carrier) 25 %Hb^S Hb^S (Affected) The chances of having carrier children is 50 % . Answer: 50 % of them will be carriers.