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MHT CET Medical202623 April 2026Morning ShiftBiologyPrinciples of Inheritance and VariationActual

A pea plant with genotype RrYy is crossed with another pea plant with genotype rryy. What will be the number of phenotypes obtained by this cross?

Options

  1. A16
  2. B12
  3. C9
  4. D4

Correct answer

D. 4

Step-by-step solution

The given cross is between a dihybrid plant (RrYy) and a homozygous recessive plant (rryy). This is a dihybrid test cross. The plant with genotype RrYy produces four types of gametes: RY, Ry, rY, and ry. The plant with genotype rryy produces only one type of gamete: ry. The offspring produced from this cross will have the following genotypes and phenotypes: RrYy : Round Yellow Rryy : Round Green rrYy : Wrinkled Yellow rryy : Wrinkled Green Thus, four different phenotypes are obtained in a ratio of 1:1:1:1 . Answer:

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