What is the number of electrons in bonding molecular orbitals and...

The total number of electrons in the F_2$molecule is 9 + 9 = 18$. The molecular orbital electronic configuration of F_2$is:$\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^{*2} \pi_{2p_y}^{*2}$The number of electrons in bonding molecular orbitals (N_b$) is the sum of electrons in \sigma_{1s}$,$\sigma_{2s}$,$\sigma_{2p_z}$, \pi_{2p_x}$, and $\pi_{2p_y}$ orbitals: $N_b = 2 + 2 + 2 + 2 + 2 = 10$ The number of electrons in antibonding molecular orbitals (N_a$) is the sum of electrons in \sigma_{1s}^{*}$, $\sigma_{2s}^{*}$, $\pi_{2p_x}^{*}$, and $\pi_{2p_y}^{*}$ orbitals: $N_a = 2 + 2 + 2 + 2 = 8$ Thus, the number of electrons in bonding and antibonding molecular orbitals are 10 and 8 respectively. Answer: 10 and 8