Identify the hybridization in BF_3 molecule.

The central atom in $\text{BF}_3$ is Boron (B), which has 3 valence electrons.

Boron forms 3 sigma bonds with 3 Fluorine (F) atoms and has 0 lone pairs.

Steric number = Number of sigma bonds + Number of lone pairs = $3 + 0 = 3$.

A steric number of 3 corresponds to $sp^2$ hybridization.

Answer: $sp^2$ hybridization