MHT CET Medical202622 April 2026Morning ShiftChemistryElectrochemistryActual
Calculate the amount of electricity required to deposit 1 mole of aluminum from a solution of AlCl ₃ .
Options
- A0.33 Faraday
- B1 Faraday
- C3 Faraday
- D1.33 Faraday
Correct answer
C. 3 Faraday
Step-by-step solution
The dissociation of AlCl ₃ gives Al ³⁺ ions. The reduction reaction at the cathode is: Al ³⁺ + 3e⁻ Al From the stoichiometry of the reaction, 1 mole of Al requires 3 moles of electrons. Since 1 mole of electrons carries a charge of 1 Faraday, the amount of electricity required is 3 Faraday. Answer: 3 Faraday