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MHT CET Medical202621 April 2026Evening ShiftChemistryElectrochemistryActual

The molar conductivity of 0.8 M BaCl ₂ solution at 25^ C is 220 ⁻¹ cm ^2 mol ⁻¹ . Calculate its conductivity.

Options

  1. A0.176 ⁻¹ cm ⁻¹
  2. B0.226 ⁻¹ cm ⁻¹
  3. C0.252 ⁻¹ cm ⁻¹
  4. D0.152 ⁻¹ cm ⁻¹

Correct answer

A. 0.176 ⁻¹ cm ⁻¹

Step-by-step solution

Molar conductivity is given by the formula: _m = 1000 M where is the conductivity and M is the molarity of the solution. Rearranging the formula to solve for : = _m M 1000 Substituting the given values _m = 220 ⁻¹ cm ^2 mol ⁻¹ and M = 0.8 M : = 220 0.8 1000 = 176 1000 = 0.176 ⁻¹ cm ⁻¹ Answer: 0.176 ⁻¹ cm ⁻¹

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