CH ₃ -CH=CH-CH ₂ -COOH What is the IUPAC name of the above compound ?

Step-by-step solution

Identify the principal functional group, which is the carboxylic acid group ( -COOH ). Number the carbon chain starting from the carboxylic acid carbon to give it the lowest locant ( 1 ). The numbering is as follows: C ^5 H ₃ -C ^4 H=C ^3 H-C ^2 H ₂ -C ^1 OOH The longest chain has 5 carbon atoms, so the root word is pent. There is a double bond starting at carbon 3 , so the primary suffix is 3 -en. The secondary suffix for the carboxylic acid is oic acid. Combining these parts, the IUPAC name is pent- 3 -enoic acid