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MHT CET Medical202625 April 2026Evening ShiftChemistryIonic EquilibriumActual

Find the pH of 0.02 M HCl .

Options

  1. A1.7
  2. B2.7
  3. C1.5
  4. D2.5

Correct answer

A. 1.7

Step-by-step solution

HCl is a strong acid and dissociates completely in aqueous solution. [ H ⁺] = 0.02 M = 2 10⁻² M pH = - ₁₀[ H ⁺] pH = - ₁₀(2 10⁻²) pH = 2 - ₁₀ 2 Using ₁₀ 2 0.3 : pH = 2 - 0.3 = 1.7 Answer: 1.7

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