Calculate the atomic radius of an element having edge length 3.61 10⁻⁸ cm for fcc structure.

Step-by-step solution

For a face-centered cubic (fcc) unit cell, the atoms touch each other along the face diagonal. The relationship between the edge length a and the atomic radius r is given by: 4r = 2 a r = a 2 2 Given a = 3.61 10⁻⁸ cm . Substituting the value of a : r = 3.61 10⁻⁸ 2 1.414 r = 3.61 10⁻⁸ 2.828 r = 1.276 10⁻⁸ cm 1.28 10⁻⁸ cm Answer: 1.28 10⁻⁸ cm