If a solution is prepared by dissolving solute in 0.3 L of water having osmotic pressure 164.1 atm at 300 K, what will be the number of moles of solute in solution? (R = 0.08205 L atm K^ -1 mol^ -1 )

Question

Quantrex Academy · Accepted Answer

Correct answer: D. 2.0

Using the formula for osmotic pressure:

\pi = \dfrac{n}{V} R T

Rearranging for the number of moles

n

:

n = \dfrac{\pi V}{R T}

Substituting the given values:

n = \dfrac{164.1 \times 0.3}{0.08205 \times 300}

n = \dfrac{49.23}{24.615}

n = 2.0

Answer:

2.0

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