What is the osmotic pressure of 0.25 M urea solution at 27^ ^ C ( R = 0.0821\ L atm mol^ -1 ^ -1 )?

Correct answer: C. 6.15 atm The osmotic pressure is given by the formula π = CRT . Given: C = 0.25 M R = 0.0821 L atm mol^ -1 K^ -1 T = 27^ ^ C = 27 + 273 = 300 K Substituting the values: π = 0.25 × 0.0821 × 300 π = 6.1575 6.15 atm Answer: 6.15 atm

MHT CET 202622 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 22 April
Shift: Evening Shift
Subject: Chemistry
Chapter: Solutions

MHT CET 2026 · 22 April · Evening Shift · Chemistry · Solutions

What is the osmotic pressure of 0.25 M urea solution at 27^ ^ C ( R...

What is the osmotic pressure of

0.25

M urea solution at

27^{}^{\circ}

C (

R = 0.0821\ \text{L atm mol}^{-1}\textK^{-1}

Options

A $3.07$ atm
B $4.10$ atm
C $6.15$ atm
D $2.46$ atm

Correct answer

C. $6.15$ atm

Step-by-step solution

The osmotic pressure is given by the formula

\pi = CRT

.

Given:

C = 0.25

R = 0.0821

L atm mol^{-1}

K^{-1}

T = 27^{}^{\circ}

= 27 + 273 = 300

K

Substituting the values:

\pi = 0.25 \times 0.0821 \times 300

\pi = 6.1575 \approx 6.15

atm

Answer:

6.15

atm

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