MHT CET Medical202622 April 2026Evening ShiftChemistryThermodynamics (C)Actual
Determine the constant external pressure required to compress 2 mole of an ideal gas from volume 10.8 dm ^3 to 5.4 dm ^3 if the work obtained is 2460 J.
Options
- A2.28 bar
- B1.14 bar
- C3.42 bar
- D4.56 bar
Correct answer
D. 4.56 bar
Step-by-step solution
Work done during compression against a constant external pressure is W = -P_ ext V . Given W = 2460 J , V₁ = 10.8 dm ^3 , V₂ = 5.4 dm ^3 . V = 5.4 - 10.8 = -5.4 dm ^3 = -5.4 L . Substituting the values: 2460 J = -P_ ext (-5.4 L ) Since 1 L bar = 100 J , we have: 2460 = P_ ext 5.4 100 P_ ext = 2460 540 = 4.555 bar 4.56 bar . Answer: 4.56 bar