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MHT CET Medical202622 April 2026Evening ShiftChemistryThermodynamics (C)Actual

For a certain reaction, the enthalpy change and entropy change are +50 kJ and -50 J/K respectively at 27^ C, What is the Gibbs free energy change of reaction?

Options

  1. A-65 kJ
  2. B35 kJ
  3. C-35 kJ
  4. D65 kJ

Correct answer

D. 65 kJ

Step-by-step solution

Given H = +50 kJ and S = -50 J/K = -0.05 kJ/K . The temperature is T = 27^ C = 300 K . Using the Gibbs free energy equation: G = H - T S Substituting the given values: G = 50 - (300)(-0.05) G = 50 + 15 = 65 kJ Answer: 65 kJ

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