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MHT CET Medical202622 April 2026Morning ShiftChemistryThermodynamics (C)Actual

Calculate the amount of work done in the oxidation of 1 mole of HCl(g) at 127^ C if 4 , HCl(g) + O ₂ (g) 2 Cl ₂ (g) + 2 H ₂ O(g) ; [ R = 8.314 JK ⁻¹ mol ⁻¹ ]

Options

  1. A831.4 J
  2. B491.6 kJ
  3. C1474.6 J
  4. D1662.8 J

Correct answer

A. 831.4 J

Step-by-step solution

The given reaction is: 4 HCl(g) + O ₂ (g) 2 Cl ₂ (g) + 2 H ₂ O(g) For the oxidation of 4 moles of HCl , the change in the number of gaseous moles is: n_g = (2 + 2) - (4 + 1) = -1 For the oxidation of 1 mole of HCl , the change in the number of gaseous moles is: n_g = - 1 4 The given temperature is T = 127^ C = 127 + 273 = 400 K . The work done is given by the formula: W = - n_g R T Substituting the values: W = - (- 1 4 ) 8.314 400 W = 8.314 100 = 831.4 J Answer: 831.4 J

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