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MHT CET 202621 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
21 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

MHT CET 2026 · 21 April · Evening Shift · Chemistry · Thermodynamics (C)

A gas is compressed by an average pressure of 0.50 atmosphere, so...

A gas is compressed by an average pressure of 0.500.50 atmosphere, so as to decrease its volume from 400 cm3400\ \text{cm}^3 to 200 cm3200\ \text{cm}^3. What will be the work done in this case?

Options

  1. A10.13 J10.13\ \text{J}
  2. B20.13 J20.13\ \text{J}
  3. C30.13 J30.13\ \text{J}
  4. D40.13 J40.13\ \text{J}

Correct answer

A. 10.13 J10.13\ \text{J}

Step-by-step solution

The work done on the gas during compression is given by:

W=−PextΔVW = -P_{\text{ext}} \Delta V

Given Pext=0.50 atmP_{\text{ext}} = 0.50\ \text{atm}

V1=400 cm3=0.4 LV_1 = 400\ \text{cm}^3 = 0.4\ \text{L}

V2=200 cm3=0.2 LV_2 = 200\ \text{cm}^3 = 0.2\ \text{L}

Substituting the values:

W=−0.50×(0.2−0.4)=0.10 L⋅atmW = -0.50 \times (0.2 - 0.4) = 0.10\ \text{L}\cdot\text{atm}

Using the conversion factor 1 L⋅atm=101.3 J1\ \text{L}\cdot\text{atm} = 101.3\ \text{J}:

W=0.10×101.3 J=10.13 JW = 0.10 \times 101.3\ \text{J} = 10.13\ \text{J}

Answer: 10.13 J10.13\ \text{J}
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