MHT CET Medical202624 April 2026Evening ShiftChemistryThermodynamics (C)Actual
Determine the temperature at which 2 moles of oxygen gas expands isothermally and reversibly from 2 dm ^3 to 20 dm ^3 performs -11490 J of work [2.303 R = 19.15 JK ⁻¹ mol ⁻¹]
Options
- A295 K
- B310 K
- C305 K
- D300 K
Correct answer
D. 300 K
Step-by-step solution
The work done during a reversible isothermal expansion is given by: W = -2.303 nRT ₁₀ ( V₂ V₁ ) Substituting the given values W = -11490 J , n = 2 mol , V₁ = 2 dm ^3 , V₂ = 20 dm ^3 , and 2.303 R = 19.15 J K ⁻¹ mol ⁻¹ : -11490 = -2 19.15 T ₁₀ ( 20 2 ) -11490 = -38.3 T ₁₀(10) -11490 = -38.3 T 1 T = 11490 38.3 = 300 K Answer: 300 K