Calculate the work done when an ideal gas expands from 1 × 10^ -3 to 1 × 10^ -2 \ m^3 at 300 K against constant pressure of 1 × 10^5\ Nm^ -2 . ?

Question

Quantrex Academy · Accepted Answer

Correct answer: D. -900 J

Work done during expansion against a constant external pressure is given by

W = -P_{\text{ext}} \Delta V

.

Given

P_{\text{ext}} = 1 \times 10^5\ \text{Nm}^{-2}

.

Initial volume

V_1 = 1 \times 10^{-3}\ \text{m}^3

.

Final volume

V_2 = 1 \times 10^{-2}\ \text{m}^3

.

Change in volume

\Delta V = V_2 - V_1 = 1 \times 10^{-2} - 1 \times 10^{-3} = 9 \times 10^{-3}\ \text{m}^3

.

Substituting the values:

W = -1 \times 10^5 \times 9 \times 10^{-3} = -900\ \text{J}

.

Answer:

-900

J

Calculate the work done when an ideal gas expands from 1 × 10^ -3...