Calculate the work done when an ideal gas expands from 1 10⁻³ to 1 10⁻² m ^3 at 300 K against constant pressure of 1 10^5 Nm ⁻² . ?

Step-by-step solution

Work done during expansion against a constant external pressure is given by W = -P_ ext V . Given P_ ext = 1 10^5 Nm ⁻² . Initial volume V₁ = 1 10⁻³ m ^3 . Final volume V₂ = 1 10⁻² m ^3 . Change in volume V = V₂ - V₁ = 1 10⁻² - 1 10⁻³ = 9 10⁻³ m ^3 . Substituting the values: W = -1 10^5 9 10⁻³ = -900 J . Answer: -900 J