An alternating voltage is given as, E=100 2 100t This voltage E is applied to a capacitor of 1 F . The current reading in an a.c. ammeter in mA is

Step-by-step solution

Given alternating voltage is E = 100 2 (100t) Comparing with the standard equation E = E₀ ( t) , we get: Peak voltage, E₀ = 100 2 V Angular frequency, = 100 rad/s The rms voltage is E_ rms = E₀ 2 = 100 2 2 = 100 V Capacitive reactance, X_C = 1 C = 1 100 10⁻⁶ = 10^4 The reading of an a.c. ammeter is the rms current, which is given by: I_ rms = E_ rms X_C = 100 10^4 = 10⁻² A Converting to milliamperes: I_ rms = 10⁻² 1000 mA = 10 mA Answer: 10