In an L-C-R series, AC circuit at resonance,

In an L-C-R series AC circuit, the impedance is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$.

At resonance, the impedance of the circuit is minimum and purely resistive, which means $Z = R$.

This condition is satisfied when the inductive reactance is equal to the capacitive reactance, i.e., $X_L = X_C$.

Since the impedance is minimum, the current in the circuit is maximum, leading to maximum power dissipation.

Therefore, at resonance, the capacitive reactance is equal to the inductive reactance.

Answer: the capacitive reactance is equal to the inductive reactance.