A series L-C-R circuit is connected to a source of alternating emf of 50 V . The potential difference across inductor and capacitor is 80 V and 50 V respectively. The potential difference across the resistor is

Step-by-step solution

In a series L-C-R circuit, the applied voltage V is given by the phasor sum of the voltages across the resistor, inductor, and capacitor. V = V_R^2 + (V_L - V_C)^2 Given V = 50 V , V_L = 80 V , and V_C = 50 V . Substituting the values: 50 = V_R^2 + (80 - 50)^2 50^2 = V_R^2 + 30^2 2500 = V_R^2 + 900 V_R^2 = 1600 V_R = 40 V Answer: 40 V