A series L-C-R circuit is connected to a source of alternating emf of 50\ V . The potential difference across inductor and capacitor is 80\ V and 50\ V respectively. The potential difference across the resistor is

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Quantrex Academy · Accepted Answer

Correct answer: D. 40\ V

In a series L-C-R circuit, the applied voltage

V

is given by the phasor sum of the voltages across the resistor, inductor, and capacitor.

V = \sqrt{V_R^2 + (V_L - V_C)^2}

Given

V = 50\ \text{V}

,

V_L = 80\ \text{V}

, and

V_C = 50\ \text{V}

.

Substituting the values:

50 = \sqrt{V_R^2 + (80 - 50)^2}

50^2 = V_R^2 + 30^2

2500 = V_R^2 + 900

V_R^2 = 1600

V_R = 40\ \text{V}

Answer:

40\ \text{V}

A series L-C-R circuit is connected to a source of alternating emf...

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