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MHT CET 202623 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
23 April
Shift
Morning Shift
Subject
Physics
Chapter
Alternating Current

MHT CET 2026 · 23 April · Morning Shift · Physics · Alternating Current

The output of a step-down transformer is measured to be 56 V when...

The output of a step-down transformer is measured to be 5656 V when connected to 1414 W light bulb. The value of peak current is (in A)

Options

  1. A12\dfrac{1}{\sqrt{2}}
  2. B13\dfrac{1}{\sqrt{3}}
  3. C122\dfrac{1}{2\sqrt{2}}
  4. D132\dfrac{1}{3\sqrt{2}}

Correct answer

C. 122\dfrac{1}{2\sqrt{2}}

Step-by-step solution

Given output power P=14P = 14 W and output RMS voltage Vrms=56V_{rms} = 56 V.

Using the relation P=VrmsIrmsP = V_{rms} I_{rms}:

Irms=PVrms=1456=14I_{rms} = \dfrac{P}{V_{rms}} = \dfrac{14}{56} = \dfrac{1}{4} A

The peak current I0I_0 is given by I0=2IrmsI_0 = \sqrt{2} I_{rms}.

I0=2×14=122I_0 = \sqrt{2} \times \dfrac{1}{4} = \dfrac{1}{2\sqrt{2}} A

Answer: 122\dfrac{1}{2\sqrt{2}}
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