An alternating voltage given as, E = 100 2 (100t) volt is applied to a capacitor of 1 F . The current reading of the ammeter will be equal to

Step-by-step solution

Given alternating voltage E = 100 2 (100t) V. Peak voltage E₀ = 100 2 V. RMS voltage E_ rms = E₀ 2 = 100 V. Angular frequency = 100 rad/s. Capacitance C = 1 F = 10⁻⁶ F. Capacitive reactance X_ C = 1 C = 1 100 10⁻⁶ = 10⁴ . The ammeter reads the RMS value of the current. I_ rms = E_ rms X_ C = 100 10⁴ = 10⁻² A = 10 mA. Answer: 10 mA