In series LCR circuit the alternating emf 'e' and the current 'i' are given by the equations e = e₀ t , i = i₀ ( t + 6 ) . The average power dissipated in the circuit over a one complete cycle of A.C is ( 60 = 1/2 )

Step-by-step solution

The given equations for alternating emf and current are: e = e₀ t = e₀ ( t + 2 ) i = i₀ ( t + 6 ) The phase difference between the emf and current is: = 2 - 6 = 3 = 60^ The average power dissipated over one complete cycle is given by: P_ avg = e_ rms i_ rms Substituting the values of e_ rms , i_ rms , and : P_ avg = ( e₀ 2 ) ( i₀ 2 ) 60^ P_ avg = e₀ i₀ 2 1 2 = e₀ i₀ 4 Answer: e₀ i₀ 4