An ac circuit contains a resistance of 1 k , a capacitor of 0.1 F and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately :

Step-by-step solution

Given L = 1 mH = 10⁻³ H and C = 0.1 F = 10⁻⁷ F . The resonance frequency of a series RLC circuit is given by f_r = 1 2 LC . Substituting the values: f_r = 1 2 10⁻³ 10⁻⁷ f_r = 1 2 10⁻¹⁰ f_r = 10^5 2 Hz f_r = 50 kHz 15.9 kHz Answer: 15.9 kHz