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MHT CET Medical202623 April 2026Morning ShiftPhysicsCurrent ElectricityActual

In Wheatstone bridge, resistance P is formed by a parallel combination of p₁ and p₂ . The Q resistance is formed by a parallel combination of q₁ and q₂ . The remaining two resistances are R and S respectively, and in the balanced condition, R S is

Options

  1. A(p₁ p₂) (q₁ q₂)(p₁ + p₂)
  2. B(p₁ p₂)(q₁ + q₂) (q₁ q₂)(p₁ + p₂)
  3. C(q₁ q₂)(q₁ + q₂) (p₁ p₂)(p₁ + p₂)
  4. D(p₁ p₂)(q₁ + q₂) (p₁ + p₂)

Correct answer

B. (p₁ p₂)(q₁ + q₂) (q₁ q₂)(p₁ + p₂)

Step-by-step solution

In the given Wheatstone bridge, the resistance of the top-left arm is formed by the parallel combination of p₁ and p₂ . Let this equivalent resistance be P . P = p₁ p₂ p₁ + p₂ Similarly, the resistance of the top-right arm is formed by the parallel combination of q₁ and q₂ . Let this equivalent resistance be Q . Q = q₁ q₂ q₁ + q₂ The resistances of the bottom-left and bottom-right arms are R and S respectively. For a balanced Wheatstone bridge, the ratio of resistances in the adjacent arms is equal: P Q = R S Subst

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