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MHT CET Medical202622 April 2026Evening ShiftPhysicsCurrent ElectricityActual

A galvanometer of resistance ' G ', is shunted by a resistance ' S ' ohm. To keep the main current in the circuit unchanged, the resistance to be put in series with the galvanometer is

Options

  1. ASG S+G
  2. BG S+G
  3. CG^2 S+G
  4. DS^2 S+G

Correct answer

C. G^2 S+G

Step-by-step solution

Let the original resistance of the galvanometer be G . When the galvanometer is shunted by a resistance S , the equivalent resistance of the parallel combination is GS G+S . Let R be the resistance connected in series with this combination. To keep the main current in the circuit unchanged, the total resistance of the modified galvanometer must be equal to its original resistance G . R + GS G+S = G R = G - GS G+S R = G(G+S) - GS G+S R = G^2 + GS - GS G+S R = G^2 S+G Answer: G^2 S+G

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