A closed loop consists of a 15\ V battery, a 5\ V battery (opposing the first), and a 25\ resistor. The current through the loop is

Correct answer: D. 0.4\ A The net electromotive force in the loop is the difference between the two opposing batteries. E_ net = 15 - 5 = 10\ V The total resistance in the loop is R = 25\ . Using Ohm's law, the current I is given by: I = E_ net R = (10)/(25) = 0.4\ A Answer: 0.4\ A

MHT CET 202625 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 25 April
Shift: Evening Shift
Subject: Physics
Chapter: Current Electricity

MHT CET 2026 · 25 April · Evening Shift · Physics · Current Electricity

A closed loop consists of a 15\ V battery, a 5\ V battery (opposing...

A closed loop consists of a

15\ \text{V}

battery, a

5\ \text{V}

battery (opposing the first), and a

25\ \Omega

resistor. The current through the loop is

Options

A $0.8\ \text{A}$
B $0.2\ \text{A}$
C $1.2\ \text{A}$
D $0.4\ \text{A}$

Correct answer

D. $0.4\ \text{A}$

Step-by-step solution

The net electromotive force in the loop is the difference between the two opposing batteries.

E_{\text{net}} = 15 - 5 = 10\ \text{V}

The total resistance in the loop is

R = 25\ \Omega

.

Using Ohm's law, the current

I

is given by:

I = \dfrac{E_{\text{net}}}{R} = \dfrac{10}{25} = 0.4\ \text{A}

Answer:

0.4\ \text{A}

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