A galvanometer of resistance 100 gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0 - 10 A. The shunt required is :

Step-by-step solution

Given G = 100 , I_g = 1 mA = 10⁻³ A , and I = 10 A . The shunt resistance S required to convert a galvanometer into an ammeter is given by: S = I_g G I - I_g Substituting the values: S = 10⁻³ 100 10 - 10⁻³ Since 10 10⁻³ , we can approximate 10 - 10⁻³ 10 . S 0.1 10 = 0.01 Answer: 0.01