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MHT CET Medical202623 April 2026Morning ShiftPhysicsDual Nature of MatterActual

An electron of mass m and a photon have the same energy E. The ratio of de-Broglie wavelengths associated with them ( _e _p ) is c = velocity of light

Options

  1. AE 2m
  2. Bc 2mE
  3. C1 c 2m E
  4. D1 c E 2m

Correct answer

D. 1 c E 2m

Step-by-step solution

The de-Broglie wavelength of an electron of mass m and kinetic energy E is given by: _e = h 2mE The energy of a photon is given by E = hc _p , where _p is its wavelength. Therefore, the wavelength of the photon is: _p = hc E The ratio of their de-Broglie wavelengths is: _e _p = h 2mE hc E _e _p = h 2mE E hc _e _p = 1 c E 2mE _e _p = 1 c E^2 2mE _e _p = 1 c E 2m

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