Statement I - When the wavelength of incident radiation in a...

According to Einstein's photoelectric equation, the maximum kinetic energy of photoelectrons is given by K_\max = \dfrac{hc}{\lambda} - \Phi, where $\lambda$ is the wavelength of incident radiation and $\Phi$ is the work function.

The stopping potential $V_0$ is related to maximum kinetic energy as eV_0 = K_\max.

If the wavelength $\lambda$ is decreased, the term $\dfrac{hc}{\lambda}$ increases, which increases K_\max. Consequently, the stopping potential $V_0$ will increase. Thus, Statement I is incorrect.

The maximum kinetic energy of photoelectrons depends only on the frequency (or wavelength) of the incident light and the work function of the material. It is independent of the intensity of the incident light. Doubling the intensity increases the number of photoelectrons emitted per second but does not change their maximum kinetic energy. Thus, Statement II is incorrect.

Both statements are incorrect.

Answer: Both the statements are incorrect.