Three charges each of +4 , C are placed at the corners A, B, C of a square ABCD of side 1 m. The electric field at the centre of the square is

Step-by-step solution

Let the center of the square be O. The distance from each corner to the center is r = a 2 = 1 2 m. The electric field at O due to the charge at A is equal and opposite to the electric field at O due to the charge at C. Hence, they cancel each other out. The net electric field at O is solely due to the charge at B. Since the charge at B is positive, the electric field points away from B, i.e., towards D. The magnitude of the electric field is given by E = 1 4 ₀ q r^2 . Substituting the values, we get E = 9 10^9 4 10