The electric potential due to a dipole at point P making an angle 120^ with the axis of a dipole is ( ₀ = permitivity of free space, p = electric dipole moment , r = distance of point P from the center of dipole) ( 60^ = 1/2 )

Step-by-step solution

The electric potential V due to a dipole at a distance r and angle from the dipole axis is given by V = 1 4 ₀ p r^2 Given = 120^ , we have 120^ = - 60^ = - 1 2 Substituting this value into the formula, we get V = 1 4 ₀ p (- 1 2 ) r^2 V = -1 8 ₀ p r^2 Answer: -1 8 ₀ p r^2