The electric potential ' V ' at a radial distance x just outside a non-conducting sphere is ( R^2)/(2 _0 x) . The electric intensity ' E ' at a radial distance x is ( is uniform volume charge density, R is the radius of

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Correct answer: A. ( R^2)/(2 _0 x)

The relation between electric field intensity

E

and electric potential

V

in a radial field is given by

E = -\dfrac{dV}{dx}

.

Given the electric potential

V = \dfrac{\rho R^2}{2\varepsilon_0 x}

.

Differentiating

V

with respect to

x

to find

E

:

E = -\dfrac{d}{dx} \left(\dfrac{\rho R^2}{2\varepsilon_0 x}\right)<br><br>

E = -

\dfrac{\rho R^2}{2\varepsilon_0} \left(-\dfrac{1}{x^2}\right)<

br>

E = \dfrac{\rho R²}{2\varepsilon_0 x²}

Answer:

\dfrac{\rho R²}{2\epsilon_0 x}

The electric potential ' V ' at a radial distance x just outside a...

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