A body of mass 1 kg is performing linear SHM. Its displacement x (cm) at t (s) is given by x=6 (100t+(π)/(4)). Maximum kinetic energy of the body is

Correct answer: B. 18 J Given displacement equation is x = 6 (100t+(π)/(4)) cm. Comparing with the standard equation of SHM x = A ( ω t + φ) , we get: Amplitude A = 6 cm = 0.06 m Angular frequency ω =100 rad/s Maximum velocity of the body is given by v_ max = A ω v_ max = 0.06 ×100 = 6 m/s Maximum kinetic energy is K_ max =(1)/(2) mv_ max ^2 Substituting the values, K_ max = (1)/(2) ×1 × (6)^2 = 18 J. Answer: 18 J

MHT CET 202623 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 23 April
Shift: Evening Shift
Subject: Physics
Chapter: Oscillations

MHT CET 2026 · 23 April · Evening Shift · Physics · Oscillations

A body of mass 1 kg is performing linear SHM. Its displacement x...

A body of mass

1

kg is performing linear SHM. Its displacement

x

(cm) at

t

(s) is given by

x=6\sin

\left(100t+\dfrac{\pi}{4}\right).

Maximum kinetic energy of the body is

Options

A $9$ J
B $18$ J
C $27$ J
D $36$ J

Correct answer

B. $18$ J

Step-by-step solution

Given displacement equation is

x = 6\sin \left(100t+\dfrac{\pi}{4}\right) cm.<br><br>Comparing with the standard equation of SHM

x = A\sin(

\omega

t + \phi)

, we get:<br><br>Amplitude

A = 6

cm

= 0.06

m<br><br>Angular frequency \omega =100

rad/s

Maximum velocity of the body is given by

v_{\text{max}}

= A

\omega<br><br>

v_{

\text{max}

} = 0.06

\times100 = 6

m/s

Maximum kinetic energy is

K_{\text{max}}=\dfrac{1}{2}

mv_{

\text{max}

}^2

<br><br>Substituting the values,

K_{

\text{max}

} =

\dfrac{1}{2} \times1 \times (6)^2 = 18

J.

Answer:

18

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