For a particle executing simple harmonic motion , which of the...

In simple harmonic motion, the acceleration of a particle is given by $a = -\omega^2 x$, where $x$ is the displacement from the equilibrium position.

At the equilibrium position, the displacement $x = 0$.

Substituting $x = 0$ in the expression for acceleration, we get $a = 0$.

Thus, the acceleration of the particle is minimum (zero) at the equilibrium position, not maximum.

The restoring force $F = -kx$ is directed towards the equilibrium position and its magnitude is maximum at the extreme positions where $x = \pm A$.

Therefore, the statement that acceleration is maximum at the equilibrium position is incorrect.

Answer: The acceleration of the particle is maximum at equilibrium position.