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MHT CET 202624 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
24 April
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

MHT CET 2026 · 24 April · Morning Shift · Physics · Ray Optics

An object is placed 15 cm from a concave mirror of focal length 10...

An object is placed 15 cm from a concave mirror of focal length 10 cm, then the nature of the image formed will be

Options

  1. Amagnified and inverted
  2. Bmagnified and erect
  3. Csmall in size and inverted
  4. Dsmall in size and erect

Correct answer

A. magnified and inverted

Step-by-step solution

Given object distance u=−15u = -15 cm and focal length f=−10f = -10 cm.

Using the mirror formula:

1v+1u=1f\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f}

1v−115=−110\dfrac{1}{v} - \dfrac{1}{15} = -\dfrac{1}{10}

1v=115−110=2−330=−130\dfrac{1}{v} = \dfrac{1}{15} - \dfrac{1}{10} = \dfrac{2 - 3}{30} = -\dfrac{1}{30}

v=−30v = -30 cm

Magnification m=−vu=−−30−15=−2m = -\dfrac{v}{u} = -\dfrac{-30}{-15} = -2

Since mm is negative, the image is real and inverted. Since ∣m∣>1|m| > 1, the image is magnified.

Answer: magnified and inverted
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