The focal length of the objective of astronomical telescope is 2 m . Under normal adjustment, length of telescope is 2.10 m . The magnifying power of the telescope under normal adjustment is

Step-by-step solution

Given focal length of the objective, f_o = 2 m . Length of the telescope under normal adjustment, L = 2.10 m . For normal adjustment, the length of the telescope is given by L = f_o + f_e . Substituting the given values: 2.10 = 2 + f_e f_e = 0.10 m The magnifying power of the telescope under normal adjustment is given by M = f_o f_e . M = 2 0.10 = 20 Answer: 20