MHT CET Medical202621 April 2026Morning ShiftPhysicsThermal Properties of MatterActual
The thermal conduction rate ' P_ cond ' of a slab is given by P_ cond = kA(T₁ - T₂) x , where ' x ' is the thickness of the slab and 'A' is the area . The term that represents thermal resistance ' R_T '
Options
- AkA x
- Bx kA
- Ck(T₁-T₂) x
- Dx k(T₁-T₂)
Correct answer
B. x kA
Step-by-step solution
The rate of heat flow (thermal conduction rate) is given by P_ cond = kA(T₁ - T₂) x . This can be rewritten as P_ cond = T₁ - T₂ x kA . Comparing this with the electrical analogy I = V R , where I is the current, V is the potential difference, and R is the electrical resistance. Here, P_ cond is analogous to current I , and the temperature difference (T₁ - T₂) is analogous to potential difference V . Thus, the thermal resistance R_T is analogous to electrical resistance R . Therefore, R_T = x kA . Answer: x kA