If two temperatures differ by 25\ ^ ^ C on Celsius scale, the difference in temperature on Fahrenheit scale is

Correct answer: B. 45\ F The relation between temperature on Celsius scale and Fahrenheit scale is given by F = (9)/(5)C + 32 For a change in temperature, the relation becomes Δ F = (9)/(5)Δ C Given Δ C = 25^ ^ C , substituting this value gives Δ F = (9)/(5) × 25 = 45^ ^ F Answer: 45\ F

MHT CET 202624 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 24 April
Shift: Evening Shift
Subject: Physics
Chapter: Thermal Properties of Matter

MHT CET 2026 · 24 April · Evening Shift · Physics · Thermal Properties of Matter

If two temperatures differ by 25\ ^ ^ C on Celsius scale, the...

If two temperatures differ by

25\ ^{}^{\circ}\text{C}

on Celsius scale, the difference in temperature on Fahrenheit scale is

Options

A $65\ \text{F}$
B $45\ \text{F}$
C $38\ \text{F}$
D $25\ \text{F}$

Correct answer

B. $45\ \text{F}$

Step-by-step solution

The relation between temperature on Celsius scale and Fahrenheit scale is given by

F = \dfrac{9}{5}C + 32

For a change in temperature, the relation becomes

\Delta F = \dfrac{9}{5}\Delta C

Given

\Delta C = 25^{}^{\circ}\text{C}

, substituting this value gives

\Delta F = \dfrac{9}{5} \times 25 = 45^{}^{\circ}\text{F}

Answer:

45\ \text{F}

Practice Thermal Properties of Matter on Quantrex Academy →

More from Thermal Properties of Matter