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MHT CET Medical202624 April 2026Evening ShiftPhysicsThermal Properties of MatterActual

The ratio of emissive power of perfectly black body at 1327 ^ C to that at 527 ^ C is

Options

  1. A4 : 1
  2. B16 : 1
  3. C64 : 1
  4. D8 : 1

Correct answer

B. 16 : 1

Step-by-step solution

According to Stefan-Boltzmann law, the emissive power of a perfectly black body is given by E = T^4 , where T is the absolute temperature. Converting the given temperatures to Kelvin: T₁ = 1327^ C + 273 = 1600 K T₂ = 527^ C + 273 = 800 K The ratio of their emissive powers is: E₁ E₂ = ( T₁ T₂ )^4 Substituting the values: E₁ E₂ = ( 1600 800 )^4 = (2)^4 = 16 The ratio is 16 : 1 . Answer: 16 : 1

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